Upward Force required to break static friction

AI Thread Summary
To determine the upward force required to break static friction and initiate movement of a 1700 lb pipe, the static friction coefficient is noted as 0.78. The force must be applied 36 inches away from the pivot point to create enough torque for movement. It's suggested to use equilibrium equations to calculate the necessary force, taking into account the distribution of weight and the rolling friction coefficient, which is not provided. A visual representation of the setup would enhance understanding and facilitate problem-solving. The focus is on achieving sufficient upward lift to overcome static friction and initiate rolling.
woodson111
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Homework Statement



What is the upward force required to make pipe start to move?

There is a fixed point and a 36 inch shaft. The force would be applied 36 inches away to the point. The load is 1700lbs. The end point only needs to come up enough so that the static friction of the pipe is broke so that they start to roll and will be close together.

Homework Equations


downward force= 1700lbs
static friction=.78 (not sure if this is right)


The Attempt at a Solution



n=1700lbs*9.8

Forceup=?
 
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Welcome to PF! Unfortunately, your question is poorly phrased--a picture would surely be most helpful. Assuming you will provide that, do show the work you have done, so help can be provided, per PF rules.
 
here is the only pic i have. from the little circles is the 36 inches. I just need enough upward lift and force so that the pipes start to move. Hope this better explains my problem.

Thanks
 

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Use one of the equilibrium equations (which one?) to solve for the force at which the shaft will just start to rotate. Assume the pipes are equally spaced. The pipes will start to roll when rolling friction is exceeded, at an angle that is not being asked for, but which could be found if you knew the rolling friction coefficient. When the force is given in pounds, do not multiply by 9.8.
 
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