I'm trying to find the points t in (0,2\pi) such that sint=sin4t. So I use the fact that sinA=sinB <==> A=B+2n\pi (n\in\mathbb{Z}), which yields t=2n\pi/3 (n\in\mathbb{Z}). The only solutions of this in (0,2\pi) are 2\pi/3 and 4\pi/3.
However, there are 7 intersection points, says the "indirect...