I am struggling through a problem in one of my designs and would appreciate some help.
Please refer to the image attached.
Problem Description:
S = Torsion spring
F = fixed point
T = tire
A tire is attached to a torsion spring through an arm as shown in the image. The torsion spring has one...
3. Find the hamilton equations
4. using 3. prove the the angular momentum in the z axis ##L_z=m(x\dot y-xy\dot)## is preserved.
I got in ##3##:
How can I prove 4?
My approach:
Let us take two orthogonal axes: x, parallel to the racket's plane and y, perpendicular to it. For the ball to not spin, the components of initial velocities of the racket and the ball along x-axis must be same. Also, as the line of collision is along the normal to the racket's...
So I am a bit stuck on this question as my result using the above equations dose not give an numerical value which I assume from the question is needed.
So here my method for solving
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On object 2: There are only 2 horizontal forces - Friction and Tension (of the spring).
T = km2g
On Object 1: There are 3 horizontal forces and the minimum value for F is when:
F - km1g - km2g = 0
F = kg(m1 + m2)
However, Solution is:
F = kg(m1 + 0.5 m2)
Any opinion?
<< Mentor Note -- thread moved from the technical forums, so no Template is shown >>[/color]
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<<Moderator's note: Moved from a technical forum, no template.>>
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