Evaluate the double integral by converting to polar coordinates

alanthreonus
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Homework Statement


Convert to polar coordinates to evaluate

\int^{2}_{0}\int^{\sqrt(2x-x^2)}_{0}{\sqrt(x^2+y^2)}dydx

The Attempt at a Solution



Really I'm just not sure how to convert the limits of integration. I know \sqrt(2x-x^2) is a half-circle with radius 1, but I'm not really sure where to go from there.
 
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By √(2x-x) do you mean just √x ?
 
A half-circle with radius 1 would be y=sqrt(1-x^2), not what you wrote.
 
Woops, I meant sqrt(2x-x^2)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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