Finding charge in a circuit with capacitors

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Homework Help Overview

The discussion revolves around a circuit involving capacitors, specifically focusing on finding the charge on a capacitor with a dielectric (C2) and the work required to remove the dielectric after the battery is disconnected. The circuit configuration includes capacitors in both series and parallel arrangements, with specific values provided for each capacitor and the voltage of the battery.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss calculating the equivalent capacitance for capacitors in parallel and how to derive the charge on C2 from the total charge. There are attempts to set up equations based on the relationships between charge, voltage, and capacitance. Questions arise regarding the interpretation of the net charge and the sum of charges in the system.

Discussion Status

Some participants have provided insights into using the ratios of capacitances to find the charges on the capacitors. However, there is a lack of clarity on certain aspects, such as the interpretation of the net charge and the equations being used. The discussion remains open with various interpretations being explored.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the information they can share or the methods they can use. There is also a noted uncertainty regarding the correct application of the capacitor equations and the relationships between the charges on the capacitors.

nautola
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Homework Statement


http://screencast.com/t/9KET4sNSAQWj
If the picture isn't showing up, the order of the capacitors is 1 -> 2 & 4 (parallel) -> 3, with a battery in the circuit.

There's a dielectric in C2 with k = 2.71.
There's a battery with v = 5.33v in the picture.
Capacitors:
C1 = 11.2 μF
C2 = 4.04 μF
C3 = 13.1 μF
C4 = 3.32 μF

The question wants to know the charge on the capacitor with the dielectric (C2).

It also asks how much work is needed to remove the dielectric from the capacitor after the battery is removed.

Homework Equations


C = Q/V
capacitor circuit relationships
U = 1/2 Q2 / C
W = -U

The Attempt at a Solution


I got a Ceq for 2 and 4, and that gave me a charge, Q, for the parallel part of the circuit, but I don't know how to separate it from there.

As for the work, I'm pretty sure I can't do that part until I finish this first part. But even then I'm not entirely sure what to do.
 
Last edited:
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hi nautola! :smile:

(http://screencast.com/t/9KET4sNSAQWj)
nautola said:
C = Q/V

I got a Ceq for 2 and 4, and that gave me a charge, Q, for the parallel part of the circuit, but I don't know how to separate it from there.

you know that 2 and 4 have the same voltage, and you know the ratio of their capacitances, so use your capacitor equation C = Q/V to find the ratios of their charges :wink:
 
I got the total charge on the center, and the ratio of the capacitances and set up a system of equations where the net charge (et charge is the charge of capacitor 1 or capacitor 3, or the middle equivalent capacitor) equals the sum of the charges. So I solved it and got that the charge on C2 should be the net charge times the ratio of C2 to C2 + C4.
But that's wrong and I don't know why.
 
Last edited:
hi nautola! :smile:

(just got up :zzz:)
nautola said:
So I solved it and got that the charge on C2 should be the net charge times the ratio of C2 to C2 + C4.

that should work
… the net charge (et charge is the charge of capacitor 1 or capacitor 3, or the middle equivalent capacitor) equals the sum of the charges.

i don't understand this … what sum? :confused:

(if you're still not getting it, show us your equations :smile:)
 

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