Finding charge in a circuit with capacitors

AI Thread Summary
The discussion centers on calculating the charge on capacitor C2, which has a dielectric, in a circuit with multiple capacitors and a battery. Participants discuss using the equivalent capacitance of capacitors in parallel and the relationship between charge, voltage, and capacitance to find the charge on C2. There is confusion regarding how to separate the charge for capacitors in parallel and how to apply the capacitor equations correctly. Additionally, the work needed to remove the dielectric after the battery is disconnected is mentioned but remains unresolved until the charge calculation is clarified. The conversation emphasizes the importance of understanding capacitor relationships and equations in solving the problem.
nautola
Messages
16
Reaction score
0

Homework Statement


http://screencast.com/t/9KET4sNSAQWj
If the picture isn't showing up, the order of the capacitors is 1 -> 2 & 4 (parallel) -> 3, with a battery in the circuit.

There's a dielectric in C2 with k = 2.71.
There's a battery with v = 5.33v in the picture.
Capacitors:
C1 = 11.2 μF
C2 = 4.04 μF
C3 = 13.1 μF
C4 = 3.32 μF

The question wants to know the charge on the capacitor with the dielectric (C2).

It also asks how much work is needed to remove the dielectric from the capacitor after the battery is removed.

Homework Equations


C = Q/V
capacitor circuit relationships
U = 1/2 Q2 / C
W = -U

The Attempt at a Solution


I got a Ceq for 2 and 4, and that gave me a charge, Q, for the parallel part of the circuit, but I don't know how to separate it from there.

As for the work, I'm pretty sure I can't do that part until I finish this first part. But even then I'm not entirely sure what to do.
 
Last edited:
Physics news on Phys.org
hi nautola! :smile:

(http://screencast.com/t/9KET4sNSAQWj)
nautola said:
C = Q/V

I got a Ceq for 2 and 4, and that gave me a charge, Q, for the parallel part of the circuit, but I don't know how to separate it from there.

you know that 2 and 4 have the same voltage, and you know the ratio of their capacitances, so use your capacitor equation C = Q/V to find the ratios of their charges :wink:
 
I got the total charge on the center, and the ratio of the capacitances and set up a system of equations where the net charge (et charge is the charge of capacitor 1 or capacitor 3, or the middle equivalent capacitor) equals the sum of the charges. So I solved it and got that the charge on C2 should be the net charge times the ratio of C2 to C2 + C4.
But that's wrong and I don't know why.
 
Last edited:
hi nautola! :smile:

(just got up :zzz:)
nautola said:
So I solved it and got that the charge on C2 should be the net charge times the ratio of C2 to C2 + C4.

that should work
… the net charge (et charge is the charge of capacitor 1 or capacitor 3, or the middle equivalent capacitor) equals the sum of the charges.

i don't understand this … what sum? :confused:

(if you're still not getting it, show us your equations :smile:)
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...

Similar threads

Back
Top