Radius of curvature of 1 MeV electron in 1 Tesla B field

AI Thread Summary
To calculate the radius of curvature of a 1 MeV electron in a 1 Tesla magnetic field, the formula r = mv / eB is used. The relativistic speed of the electron is approximately 0.941 times the speed of light (c). The momentum (p) is calculated using p = m0v / sqrt(1 - v^2/c^2), resulting in a value of 7.59E-22 kg m/s. Given the charge of the electron (e = 1.6E-19 C) and the magnetic field strength (B = 1 T), the expected radius of curvature is approximately 4.74E-03 m. The calculations confirm that the expected value aligns with the derived results.
tuathan
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i need to calculate radius of curvature of 1 MeV KE electron in 1 Tesla magnetic field.

r = mv / eB

what is the (relativistic) speed, v, of the electron? (ans: 0.941 c ??)

then i think you use p(rho) = mo. V / sqrt (1 - v^2 /c^2) = mv (ans: 7.59E-22 kg m/s)

e = 1.6E-19 C
B = 1

please show calculation of radius of curvature..

(expected value for r: 4.74E-03 m ??)
 
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