Radius of curvature of 1 MeV electron in 1 Tesla B field

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SUMMARY

The radius of curvature for a 1 MeV kinetic energy electron in a 1 Tesla magnetic field is calculated using the formula r = mv / eB. The relativistic speed of the electron is approximately 0.941c, leading to a momentum p of 7.59E-22 kg m/s. Given the charge of the electron as 1.6E-19 C and the magnetic field strength as 1 T, the expected radius of curvature is 4.74E-03 m, confirming the calculations presented in the discussion.

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tuathan
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i need to calculate radius of curvature of 1 MeV KE electron in 1 Tesla magnetic field.

r = mv / eB

what is the (relativistic) speed, v, of the electron? (ans: 0.941 c ??)

then i think you use p(rho) = mo. V / sqrt (1 - v^2 /c^2) = mv (ans: 7.59E-22 kg m/s)

e = 1.6E-19 C
B = 1

please show calculation of radius of curvature..

(expected value for r: 4.74E-03 m ??)
 
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