Thermal coefficients of expansion

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving thermal expansion, specifically focusing on a brass rod and a copper sheet with a hole. Participants are exploring the temperature change required to close a gap created by the differing thermal expansion of the two materials.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants express confusion regarding the correctness of the equation related to linear expansion. Others question the dimensions provided in the problem, suggesting they may be unrealistic. There is also a request for clarification on the meaning of variables in the thermal expansion formula.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the formula and its application. Some guidance has been offered regarding the correct equation for thermal expansion, but there is no consensus on the understanding of the concepts involved.

Contextual Notes

Participants are grappling with the implications of the large dimensions given in the problem, which may affect their understanding and approach to the thermal expansion concepts being discussed.

Brian13
Messages
4
Reaction score
0

Homework Statement


A brass rod (linear expansion coef 19*10-6/°C) has a radius of 8139 cm and a copper (linear expansion coef 17*10-6/°C) sheet has a hole or radius 8139+8.86cm. What temperature change (K) is required to close the gap?

Homework Equations


ΔL/Lo = αΔT?

The Attempt at a Solution


I'm not even sure if the equation is right, so I'm really confused. Thanks for the help!
 
Physics news on Phys.org
Brian13 said:

Homework Statement


A brass rod (linear expansion coef 19*10-6/°C) has a radius of 8139 cm and a copper (linear expansion coef 17*10-6/°C) sheet has a hole or radius 8139+8.86cm. What temperature change (K) is required to close the gap?

Homework Equations


ΔL/Lo = αΔT?

The Attempt at a Solution


I'm not even sure if the equation is right, so I'm really confused. Thanks for the help!
That's some rod, if it has a diameter of over 16 meters!

Are you certain these are the dimensions for this problem?
 
I'm positive!
 
The equation is not correct. It should be:
$$L=L_0(1+\alpha \Delta T)$$So, if the temperature rises ΔT, in terms of #\Delta T#, what it the new radius of the rod? What is the new radius of the hole in the sheet?
 
I'm not entirely sure. I don't really understand the formula, so I'm having a hard time really wrapping my mind around it. I don't know what the L represents.
 
Brian13 said:
I'm not entirely sure. I don't really understand the formula, so I'm having a hard time really wrapping my mind around it. I don't know what the L represents.
Please say in words your understanding of the concept of thermal expansion.

Chet
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
Replies
28
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
3K
  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 4 ·
Replies
4
Views
8K