What is the equation for torque in a system with two blocks and a pulley?

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Homework Help Overview

The discussion revolves around understanding the equation for torque in a system involving two blocks and a pulley. Participants are exploring the dynamics of the system, particularly how forces and torques interact.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants have attempted to formulate equations involving torque and forces acting on the blocks and the pulley. There are questions regarding the assumptions made about tension and equilibrium, as well as confusion about which forces contribute to torque.

Discussion Status

Several participants have provided insights into applying Newton's second law to the blocks and the pulley, suggesting a combination of equations to solve for unknowns. There is ongoing exploration of the relationship between torque and linear acceleration, and how to incorporate the moment of inertia of the pulley into their equations.

Contextual Notes

Participants are navigating constraints related to the assumptions about tension in the ropes and the rotational inertia of the pulley, particularly in the context of different shapes (hollow vs. solid cylinders). There is a noted lack of consensus on the correct approach to integrate torque with Newton's laws.

TBBTs
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Homework Statement



http://imgur.com/MaT4N

MaT4N.png



Homework Equations



Torque = Fr

The Attempt at a Solution



1) I tried
m2 g r - m1 g r = 1/2 M r^2 * (acceleration / r)
didn't work

2)I tried replace the moment of inertia equation to above equation,still didn't work
 

Attachments

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TBBTs said:
1) I tried
m2 g r - m1 g r = 1/2 M r^2 * (acceleration / r)
didn't work
You cannot assume that the tension in the ropes equals the weight of the blocks. If that were true, the masses would be in equilibrium, not accelerating.

Instead, apply Newton's 2nd law to each block and to the pulley. Combine those three equations to solve for the unknowns.
 
Hi!
I tried this m2gR - m1gr +mgR =0

I am confused about which forces has torque on this problem?
How do I suppose to set up with an equation with both torque and Newton's second law?
Thanks!
 
Also,I am still confused about second part. Thanks
 
TBBTs said:
Hi!
I tried this m2gR - m1gr +mgR =0
Not sure what you're doing here.
I am confused about which forces has torque on this problem?
Torque is only relevant for the pulley. The forces creating the torque on the pulley are the rope tensions on each side of the pulley.
How do I suppose to set up with an equation with both torque and Newton's second law?
For the two blocks, you'd use the usual form of Newton's 2nd law: ΣF = ma

But for the pulley, you'll need the rotational form, which uses torque, rotational inertia, and angular acceleration: ΣTorque = I*alpha.

TBBTs said:
Also,I am still confused about second part. Thanks
To solve the second part, you'll need to replace the rotational inertia of the pulley with that of a hollow cylinder. Then you'd have to determine whether that causes the acceleration to increase, decrease, or remain the same. (Hint: How does the rotational inertia of a hollow cylinder compare to that of solid cylinder?)
 

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