H012 said:
You still want me to lift the wire at TS20 first before I try the inductor?
no, not for this test
we'll check for those voltages
and then hopefully see just how much the current shakes your coil
hopefully you can do it on a machine with open
contacts relays where you can see the arcing
if this little bit of added impedance affects arc intensity that's another clue
Tom.G said:
Don't bail out on us! You are making valuable contributions.
Thanks.. i tend to get scrambled
that's why i stick to basics
how's this for a hypothesis to check out, if those voltage tests on the caps rule out gross malfunction like sticking contacts ?
Just a hypothesis at this point...
<<<<<<<<<<<<<start hypothesis>>>>>>>>>>>>>>
The initial braking current might be quite high .
The motor becomes an induction generator that gets very nearly shorted out by those 500 uf capacitors in parallel.
We think of those capacitors as 2.65 ohms of Xc, but that's at 60 hz steady state.
At the instant of NC contact closure the capacitor (if it's discharged) is very nearly a short circuit
so change your thinking from steady state 60 hz to millisecond by millisecond
Instantaneous AC is a lot like DC
if the voltage at motor terminals if high on the sinewave at instant T's NC contact closes, we have maybe 150 volts applied instantaneously to a discharged capacitor
and the only thing limiting current is the internal impedances of the motor and the capacitor (well, plus the wires)
We'd like to think current would only be as much as LRA , probably thirty amps or less
but the motor is likely capable of a lot more
i'm no expert at fault current calculations
so have searched for general info on induction motor fault current
http://ee.lamar.edu/gleb/power/Lecture%2012%20-%20Symmetrical%20faults.pdf
4/29/2010
Fault current transients in machines
It is possible to observe the three periods of fault current if the rms magnitude of the AC component current is plotted as a function of time on a semilogarithmic scale.
It is possible to determine the time constants for the three periods...
The AC current flowing in the generator during the subtransient period is called the
subtransient current and is denoted by I”. This current
is caused by the damper windings of synchronous machines. The time constant of the subtransient current is denoted by T” and it can be determined from the slope.
This current may be 10 times the steady-state fault current
Fault transients in induction motors
An induction motor is an AC machine that has only damper windings on its rotor. Since
damper windings are major source of current during the subtransient period, the induction motors in a power system should be considered during calculations of subtransient currents flowing in faults.
Since currents in a damper winding are of little importance during the transient and steady-state periods of faults, induction motors may be ignored in fault current analysis after the subtransient period
I believe your motor is capable of 100 amps of fault current for a fraction of a line cycle and that "subtransient current" may be what is wrecking your contacts..That much current will make an impressive arc like you report seeing .
Your clamp on ammeter will not report that transient, instead it'll average a few cycles and report that smaller number.
That transient is significant to the poor little relay contact though, because relay contacts don't just close and stay closed, they bounce for a millisecond or two.
Every bounce interrupts that subtransient current and makes sparks
after a few milliseconds the current settles down and the contact quits bouncing and the motor slows to a stop as intended.
Svein and TomG you guys pointed the way to this one
if it turns out this is the trouble the fix should be easy Limit subtransient current.
That 4 inch 100 turn coil i think should oppose instantaneous current rise , it's around 1.8 millihenries i think which is not quite 1/5th of the 10mh TomG measured on a similar size motor
TomG measured the motor's steady state reactance . Subtransient reactance will be several times smaller. So that coil might roughly halve subtransient current? It's hard to judge an arc, but maybe we'll be lucky and the difference will be noticeable. Again there'll be some randomness to it depending where in the line cycle the contact closes so watch several sweep cycles.
Hopefully we can play with combination of inductance and resistance to reduce contact arcing and still give desired coastdown.<<<<<<<<<<<<<<end hypotheses>>>>>>>>>>>>>>
If testing proves me 100% wrong, well, won't be first time !
sanity check :
TomG measured 10mh
which at 60 hz is 3.77 ohms, 120 volts / 3.77 ohms is 31.8 amps and HO12 reported 29
If X'' is 1/10 of X
steady state, then X'' is ~0.3 ohms
and our 1.8mh coil is 0.69 ohms ..
What will be rate of current rise through our 1.8 mh coil and (guess at motor's subtransient reactance of ) 1 mh X'' ?
E = L X rate of change of current
so rate of change of current = E / L
without coil 150V / 1mh =150 amps per millisecond
with coil 150V / 2.8mh = 54 amps per millisecond
we might need a core...
maybe a ferrite toroid from an old CPU power supply?
What do you guys think ?old jim
ps make sure all the turns go same way on that coil - don't use lampcord with the two wires twisted together at far end, that cancels the inductance
old jim