Force Definition and 1000 Threads

For practice I did the following problem: Solving this problem mechanically was simple enough using the following force diagrams: Then $$F_{net_M} = T - Mg = 0$$ Due to the stationary condition $$T = mg$$ and $$F_{net_m} = T = ma_c$$ $$T = ma_c$$ Because centripedal acceleration is...

So I'm familiar with the magnet falling through a copper tube demonstration that shows the induced magnetic fields slowing the magnet down. I know that this experiment is also possible with a conducting coil as long as the coil forms a closed circuit. I'm trying to find a way to calculate the...

Its Good to be Back! From Resnik, Fundamentals of physics: Consider a particle of mass m, moving along an x-axis and acted on by a net force F(x) that is directed along that axis. The work done on the particle by this force as the particle moves from position ##x_i## to position ##x_f## is given...

(My multipart question is from a very naive perspective, so sorry if it is rife with misunderstandings. Please answer conceptually, with as few & as simple equations as possible. I think that all of the answers to these questions should be understandable to a high schooler, though maybe the...

Hi everyone, I'm interested to know how much kilograms force an average car can produce. I made the following calculations to answer my question but I'm not sure if I'm right or wrong! Imagine we have a 1.8L engine that can produce a max torque of 155 nm @ 4250 RPM. 1st gear ratio = 3.455...

The answer key is zero because the areas are above and below x-axis and have equal magnitude so canceling out each other. But I am confused about the solution Area 1 is above x-axis but I think the work done is negative since the sign of ##F## and ##x## is opposite. Work done on area 2 is...

This is problem 49 in chapter 6 of "Physics - 9th edition". A similar question was asked here several years ago (although with a different height). The figure is below. I added point A and angle \theta . The solution is pretty easy. For the purpose of my discussion I'm assuming that the height...

I am confused how I am supposed to figure out the answer if I do not know the mass of the earth? Do I just set it to 1 and use m1 and m2 as ratios?

this is my work but the answers say 11 m/s^2 so I made an error somewhere. Also if someone could help me with solving the direction for the acceleration, that would be greatly appreciated.

hello guys can someone verify my solution (in the picture) whether the solution is correct or I guess the steps followed would be enough. There is no solution in the book for this one but wanted to be sure. Thanks in advance

v(20)=288000 m/s=80000km/h a=(80 000-0)/(20 -0)=4000 m*s^(-2) F=m*a=0.0005*80 000 which doesn't fit any answers

Summary:: In a mass-spring system they talk about 'magnitude of dynamic force', what is meant with that? Hi! In a mass-spring system I read about the term: "magnitude of dynamic force" (see sketch). What is meant with that? I the end this is used to determine the accuracy as I understand it...

Hi All I was wondering if anyone can assist with a task of calculating whether an MDF unit will tip over if fixed only to the wall behind it with mechanical fixings as shown below. And what force will be required to do so. I've given it a try. Let me know your thoughts, would be much...

For objects traveling north or south, the Coriolis force makes sense. The velocity of the Earth's surface changes with latitude, causing an object to drift east or west relative to the Earth's surface. However, when an object is traveling east or west, the latitude is not changing. How would...

Since no body accelerates so net force is zero. Force on each mass is zero. T1 and T2 both are 60N. Edit: since there is a force applied so there is acceleration on friction less surface.

I tried solving it but I don't know how to start because I think that the given values are insufficient. I first tried to compute for individual forces of C, D, and F but I can't their values.

The answer should be no change but we know ##F=ma##. In this eqn when acceleration increases mass decreases for same force. So why not here? If normal is doubled ##\mu## should be halved.

The number of papers on maximum force c^4/4G and similar limits in general relativity is growing. Last year there were A. Jowsey et al, arXiv:2102.01831 V. Faraoni, Phys Rev D 103, 124010 (2021) C. Schiller, Phys Rev D 104, 068501 (2021) V. Faraoni, Phys Rev D 104, 068502 (2021) C. Schiller...

Hello, I would like to ask one question. What is the equation for the lift force of a rotating sphere when flying through the air: m = 0.25 g v = 130 m/s angular velocity = 105 rad/s radius = 3 mm air density = 1.2292 kg/m^3 air pressure = 101200 Pa air temperature = 15 °C = 288.15 K If anyone...

I recently encountered this problem on a test where the solution for the above problem was given as follows: $$F= \frac{Gm_1m_2} {r^2} $$ (1) but $$ m=\frac{4}{3}\pi R^3 $$ substituting in equation (1) $$F= \frac{{G(\frac{4}{3}\pi R^3\rho})^2 }{2R^2} $$ where r=radii of the two spheres m=mass...

F.B.D Of first block (I have shown only the horizontal Forces) f1(max) = μ (1kg)(g) = 0.5 * 10 = 5N F.B.D Of the second Block f2(max) = μ (3kg)(g) = 15N Now the string will become taut and the tension will start acting when f = t = 5N But for 0<f<5N there will be no motion between the 1 kg...

Since the question says that "velocity along the cylinder axis" and "magnetic field perpendicular to the cylinder axis". So cross product of velocity and magnetic field becomes their magnitude. ##\vec v\times \vec B=||v|| \\ ||B||## So ##\vec F=qvB## ##mg=qv\frac{\mu_0 nI}{4\pi r}## At first...

My attempt : ##\frac{\vec Ft^2}{2}=m\vec s## ##s=\frac{Ft^2}{2m}## ##P=\frac{W}{t}## ##k=\frac{\vec F\cdot \vec s}{t}## ##k=\frac{F^2t^2}{2mt}## ##k=\frac{F^2t}{2m}## ##F=\sqrt{\frac{2mk}{t}}## But there was an option which was ##2\sqrt{\frac{mk}{t}}##. And my assumption was that it was...

I don’t know what is contact force. Are friction and normal forces called contact forces? And we have to take the resultant of the two to get the net contact force?

$$a= -40/(10+6+4)$$ $$a=-2 m/s^2$$ Taking one mass of 10 kg. $$T-40=10(-2)$$ $$T=20 N$$ This is correct. But if I make the eqn of the system then $$-40+T-T+T-T=20(-2)$$ I have also drawn the diagram. It looks like the second body m2 is subject to no force. But it’s accelerating. How?

Q1a) - My current wrong answer is <-5.9e7, -3.3e8, -2.17e8> I used the Fnet = Gm1m2 / d^2 <unit vector> But i keep getting a dif answer each time Q2a) - I thought i could find net force and then divide it by the mass, and multiply it by the time interval. However I got the answer <-4.5, 4.5...

Hello All, :) Please see the picture , input force F1 and area A1 and second area A2 are all same for 3 cases . in case 2 and 3 , red open outline represents a free-to-move , ie , "T" piece move upward for the 1st case , output force F2 should be F2=A2/A1 x F1 , by pascal's principle ...

Hello All, pls see picture , input force F1 and area A1 and second area A2 are all same for 3 cases for the 1st case , output force F2 should be F2=A2/A1 x F1 , by pascal's principle , what about output forces of F3 and F4 ? can be same as F2 ? how i calculate them ? thanks

The solution is : The pressure inside the solid is zero and outside it equals atmospheric pressure, 1.01 × 10^5 Pa. Thus, the force is given by: F =pA = 1.01 × 10^5 × (0.25)^2 = 6.3 × 10^3 N I do not understand why only the area of one cube is used in the solution, should it not be the area...

My solution was that there would be a force of 0 Newtons on the bolt as the bolt is not moving. But this answer is wrong. Where am I going wrong?

Hello everyone, I know that GR equations are complicated and beyond my scope. But does GR give a simple gravitational equation: Force (as we know it) as a function of distance? (without any complicated tensors). - If yes. What is the equation? Does it give us something similar to Newtons...

I'm a bit confused about what difference there is (if any) between charge and force carriers. I imagine charge as a field around a particle that pushes or attracts other particles. But we're also told that bosons mediate the forces by exchanging. So there seems to be a redundancy unless charge...

I have to calculate force required to drive the trommel? I don't know how will i calculate the kinetic coefficient of friction of bearings? can some please guide me?

Say there is a gas made up of two gas molecules: Molecule A and Molecule B. Molecule A has a mass: ma and mole fraction: na. Molecule B has a mass: mb and mole fraction: nb. The gas is at thermal equilibrium and has a constant temperature throughout itself (T) everywhere. It is placed in a...

I'm trying to calculate the maximum Force in PSI applied to the transom of a planing boat under acceleration using F=ma. boat mass is 300kg accelerates from 0 to 10m/s in 6 seconds F=ma -> 500N = 300kg *(10m/s/6s) = 112.4045lbf the contact area between the boat transom and motor is 1000 mm2 =...

Hello ,all I'm calculating the force that required to push steel rod up 50 cm into water filled steel tank . pls see picture . If i exclude negligible friction force (which is friction between steel rod and water sealing gaskets ) Total Force = Force to lift 40 kg rod + Fluid Force...

I have no idea what to do but the answer is V=V0+ bt +(ct^3)/3

The force exerted downwards on the scale by the chain when it is kept on it would be Fg= Mg =λLg where λ is the linear mass density However when the chain is dropped onto the scale it exerts an additional force due to its change in momentum The force exerted by each part of the chain would...

When the Webb is at a point on its L2 orbit, (not at L2), what direction is the centrifugal force vector compared to the direction of the combined earth-sun gravity vector on the opposite side? Is the direction of this centrifugal vector ALWAYS parallel to the sun-earth plane? or is it always...

Summary:: I'm on a high school robotics team and this year one of the challenges is to have a robot that can pick up balls and shoot them into a large bowl about 9 feet above the ground. We are planning on using flywheels to launch this ball, which we will also have to figure out how to give...

I have used the work energy theorem like all source have shown me an have arrived at the right answer where work one by all the forces is the change in kinetic energy -1/2kx^2 - umgcosΘx +mgsinΘx = 0 is the equation which becomes -1/2kx -umgcosΘ+ mgsinΘ = 0 where k= spring constant u=...

in a cours of electrostatic when we have a positive charge and we bring another one (also postitive)we have to do work and apply a force that equals the force of repultion over the distance which seems weird because if we do that the net force will be equal to 0 and the charge will not move can...

I have done this question and also seen the model answer but i just want to check my method is ok. I differentiated the position vector twice and multiplied by m to get the force F. I then used the determinant method to find the curl of F which i found to be zero thus proving the force is...

hi guys one of my friends asked me about the origin of the electromagnetic induction, I know somehow that its related to the Lorenz force as the electrons in the conduction band of say the coil interact with the magnetic field ,which results in separation of electrons and positive ions which...

How did you find PF?: Google Hi 👋 I have a question 🙋‍♀️ that’s needs help Can I calculate the following ? 1. A person slams a door gate 2. Calculate the force given the height and weight of a person , and the area of the door gate 3. How to calculate the decibel produced by slamming...

May I ask if the following process is correct? Given: F=ma Apply an impulsive force using the dirac delta near 0 (with F nearly constant over the tiny impulsive interval) ma = Fδ(t) This is a second order differential equation with a forcing function. However, I cannot readily integrate...

Since the airplane is flying at a constant speed, then the lift force equals the weight of the airplane. This means that the lift force prior to acceleration is the mass * gravity constant = 29400 N. When the airplane increases horizontal speed, the lift force increases to 30 kN. This means...