Pulleys Definition and 375 Threads

So I labelled all the springs from 1 to 4. Since the force is gradual, at equilibrium : ##F = k(x_2+ x_4) - - - - (1)## Now we need to relate the different extensions of the springs: ##kx_1 = kx_4## (same string) ##x_1 = x_4 (2)## ##kx_2 = 2kx_1## ( ideal pulley) ##x_2 =...

Dear all, I have the following problem: I need to find the compression "C" in the mast and the angle that the masts makes with the horizontal (X degrees). I know that the tension in the ropes "T" are of the same magnitude on both sides of the pulley, but I am struggling with finding C and X...

I'm struggling to get to the correct answer, which I posted down bellow. The pulleys are ideal, so I figured that m₁ and m₂ will both move upwards (towards the ceiling?) with the acceleration a, while m₃ will move downwards with the acceleration -a. Let T be the tension in the string which...

Hi, If i have a system that consists of 2 pullies and 3 masses, what is the tension on each part of the string? I know that for 2 masses hanging on either side of a pulley, the tension is the same. But for 3 masses, and 2 ideal pullies(no friction) and inextensible string, is tension the same...

For this problem, The solution is, However, how do they know the block B will move up and block A will move down? The masses of each are not given so could be the other way round if ##m_b > m_a##? Also how do they know that if block B moves up by 1cm, block A will move down by 2cm? Many thanks!

I'm not really struggling with the question but the coordinate systems involved more so. So due to the modelling assumptions we know that the tension will be equal throughout the rope so we can use f = ma on each particle respectively and solve the resulting equation (as acceleration will be...

I used the regular way of solving problems with pulleys. I tried to find the tension forces, which must be the same in the rope, but I get it wrong

I know that the tension from pulley B (T1) has to be equal the m*g of m1 for m1 to have acceleration = 0. But i can't figure how this works because the m2 is already heavier. And so the block(M) has to be negative weight?

I used m1=m2=15,0kg System: FBD: Note: I believe I have solved a) correctly and am more confused about b). a) I started with drawing the FBD. Knowing that the net sum has to be zero for the system to be at rest I used the left mass to find the tension on the rope: S1 = G1 = 15kg*9,81m/s2 =...

I don't know what to do as I know the forces acting on it but not the scalar like I just don't understand the question with two different pulleys I know the tension same everywhere

hi,i have this question : m1=3kg m2=6kg m3=20kg there is no friction between m3 and the floor. what is the acceleration of each block? my attempt is : the pulley that moves is moving downward at the acceleration of m3. so the system of m1,m2 is moving downward at the acceleration of m3, then i...

Someone pls solve this. I've done it but I'm not sure if it's correct. Thanks!

> The set up: At left end, the rope is pulled down with a distance $dx_1$ by a force of constant magnitude $F$, the mass of $M$ is wrapping around by rope on the right and moves up by a distance $dx_2$ due to this. Problem: Find relate the two displacements. I thought of applying energy...

I have to apologize if the diagram is awful: I drew it for the sake of asking... I am analyzing the rope that is hanging the pulleys. From the diagram, the pulley at the left (let's call it L), has two objects with mass M at both ends. The pulley at the right (let's call it R), has an object...

hey there, I am confusing what is the right answer to this system of mass, I solved it a couple of time and I got different answers. can you help me with that? I need to find the expression of the acceleration of the 2 masses. thanks a lot,Adam.

I don't understand the working shown on the website (seen above). Firstly, they establish 'up' as the positive direction for acceleration, so A is +4 and D is -4. They create two points, P and Q, and set acceleration values for them. I understand that connected particles have the same...

Answer: E My solution: 1) Load 2q: Y direction: $$ T_1cos\alpha=mg + 2Eq$$ 2) Load q: Radial direction: $$ T_2-\frac{Fel}{sen\alpha}-\frac{Fmag}{cos\alpha}-\frac{mg}{cos\alpha}=\frac{mv^2}{l}$$ $$T_2cos\alpha=\frac{Fel}{tg\alpha}+Fmag+mg+\frac{mv^2cos\alpha}{l}$$ 3) Stem connected to...

Help, this one is completely different, the weird pulley is making it hard for me and I don't even know what to do with it and where to start. The answer is 185N but I want to know how.

Torque on driver T = 2300N x .2m = 460Nm Torque on drum T=2300N x .6m T = 1380Nm Not sure how to calculate friction force on these...Do we have to assume a contact angle of 180 degrees if nothing is given or is that even required? Not sure what a free body diagram would look like for this.

How do you set the direction for this problem? Do you look at the motion of the block? If you set right positive, does that automatically makes upward motion positive? I set right as positive and up as positive for this problem. However, my answer was wrong. Textbook solution set right as...

For the official answer, I would appreciate an explanation as to why there's a division by 2 in the constraint equation for the total length of the strings, and why the way I wrote my constraint equation is incorrect.

i tried with conservation of energy. ##E_i = 0 ## ##E_f = 2 m v^2 - 2mgh - 2mg(\sqrt{h^2 + l^2} - l) ## ## v = \sqrt{g(h - l + \sqrt{h^2 + l^2})} ## Is it right?

if the ends P and Q are being pulled down with a uniform speed its acceleration is zero and hence the Tension in the string will also be zero and if this is the case which force will make the block of mass M rise? is this a fatal flaw in the question?

if the tiny block moves downward by an amount x, the wedge should also move forward by the same amount x as they are connected by the same string whose length has to remain constant, (by differentiating it wrt time we get speed) hence I concluded that v1 = v2, but my book says otherwise what is...

I'm wanting to get a winch for my truck for vehicle recovery, but they are expensive. I know if I get a couple of snatch block pulleys, I can get a "smaller" (and less expensive) winch. My problem is that I don't know if the cable and pulleys need to be rated at or above the winch capacity, or...

Find the acceleration of block A and B, given that the mass of pulleys and strings are negligible.. I could see that the block B has gravity acting on it, therefore the gravitational force on the block ##B## is ##F_B = 5 g## and hence the acceleration is ##g##. From the pulley to which...

The figure represents a system composed of two ideal fixed pulleys that support three masses A, B, and C of the same mass M, suspended by light and inextensible threads. Massor A is simultaneously suspended by two wires, one connected to massor B (wire 1) and the other to massor C (wire 2). We...

Since 2nd pulley accelerates downward with the same acceleration of m1, and because the string around pulley has a constant length, it must be that a2=−a1+ar and a3=−a1−ar, where ar is the relative acceleration between the pulley and m2. From the above 4 equations, we are supposed to determine...

I know that if A moves down 1 unit b will move up square root of 2 and 1kg will moves up 2 unit

I have a question about the following 33 and 34. For number 33 I think the answer is B because you have to life up against the force of gravity. While with A you have gravity helping you out. The correct answer is A but I am not sure how. for 34 I think B because you have an extra pulley so...

I solved the last part of the previous question, But I got no idea how to start solving this question Like how the rope is being attached, is it attached to the inner disk or the outer one.

I tried to solve The system of torque as following. I labelled pulley one is the one in the left, and two as the one on the right. α=a/R t1=(-F+T1) R=MR^/2α. So -F+T=Ma/2 for pulley 2 (T1-T2)R=MR^2/2. So T1-T2=Ma/2 for The box T2-mg=ma add the last two equation, to get that T1-mg=Ma/2+ma...

Free body diagram is below, but I have confusion about the tension. The tension on the block and pulley should always be the same by Newton third law. so T1=T1' and T2=T2'. Part B) The system is in equilibrium so net torque on each pulley is equal to zero. Therefore T1'=T2' and T2'=T3. Applying...

Hi. I assume that vector summation of the centrifugal forces acting on the belt, on pulley A and B, equals to zero. Is Centrifugal force on pulley A static or dynamic force? What would, hypothetically, happen if the sum centrifugal forces acting on the belt are not zero? Could some kind of...

For the a part of the first problem I did this: mgsinθ < µk*mgcosθ Sinθ < µk*cosθ Tanθ < µk so θ should be less...

I've done this exercise twice now, the answer is 1.4m/s but I get 1.64m/s. It's too far off to be rounding error. 1. I don't use energy consideration, because I don't have a clue how that would work. 2. I still need to know what's wrong with my current way of solving this. Any help is...

Magnitude of acceleration of system: a = (4.59kg - 1.71kg)(9.81N/kg)/(4.59kg + 1.71kg) = 4.48 m/s^2 Velocity of lighter mass when heavier one hits the ground: vf^2 = vi^2 + 2ad = 0 + 2(4.48m/s^2)(2.60m) vf = 4.83 m/s [up] I am not sure what to do from here? I don't really understand what...

Homework Statement: In Figure 3-25, the weights of the objects are 200 N and 300 N. It is considered that the pulleys have no friction and that their masses are negligible. Pulley P1 has a stationary axis, the P2 pulley can raise or lower freely. Calculate the tensions FT1 and FT2, as well as...

Problem Statement: In the arrangement shown in the figure, a block of mass m=2kg lies on the wedge of mass M=8kg.Find the initial acceleration of the wedge. Assume pulleys and thread massless and surfaces smooth. Relevant Equations: FBDs

So, there are is a type which I couldn't understand. 1: (I don't know this type name is, so tell me please) So, the books says if you push the rope, you will double your force, but instead, for every x distance you push, it will go x/2 distance(their work is the same), which I couldn't...

Equation 1: T = Ma1 Equation 2: mg - 2T = ma2 Equation 3: a1 = 2a2 Since a1 = 2a for equation one I get T = 2Ma1 mg - 4Ma1 = ma1 mg = 4Ma1 + ma1 mg = 4a1(M+m) a1= mg / 4M+m Not sure if this is correct. Can someone please help to make sure I'm doing this right? Thanx

Homework Statement I have a question about the pulley problem in the attachment. Homework Equations This question can be answered using equilibrium of forces, namely Fx = 0 and Fy = 0. The Attempt at a Solution The answer key states that for the sum of the x-components, we should use the...

Homework Statement Homework Equations F = ma The Attempt at a Solution I couldn't draw the freebody diagram. There's this weight of mass m, which is mg, downwards from m and there's tension T to upwards. This T affects mass M in the +x direction, but how could i find out the normal force...

Hey guys What's is the formula to find the force(torque) to throw a mass in the air that is 500kg/m(3) with 2 pulley and a belt. Thanks

Hello there, i need some help on my homework. there's no given numbers that's why it's hard for me to answer this one. Two pulleys with radii r1 and r2 rotate at angular speeds of w1 and w2. if the pulleys are connected by a belt, show that r1/r2=w2/w1

Homework Statement Sorry for bad english[/B] There is serie of mass and pulleys. We Know we have more than two masses. System is balanced.We take m(m<<1) from on of the masses and add to another one. a) prove all the masses except these two have downward accleration b) prove mass with heavier...

Homework Statement Homework Equations xcxcxcxcxcxcxcxcxcxcxc[/B]The Attempt at a Solution My attempt: Let displacement of A be x m, Let displacement of B be y m, and Let displacement of C be z m. Step2: [/B]a+b+c+d=(a+x-y)+(b+x)+c+(d+z) 2x-y=-z Differentiating LHS and RHS components...

Homework Statement Under the action of force P the constant acceleration of B is 6 m/s^2 up the incline as in figure. For the instant when B's velocity is 3 m/s up incline, what is the velocity of point C? How do I solve this using constraints? [/B] Homework Equations For a pulley system ΣT.v...