ok, for 2nd order differential equations, if we have repeat roots, like for example y" +4y = cos2x
, we would have repeat roots +2i,-2i.
so how do we try for the particular solution?
i tried Acos2x + Bsin2x, it all canceled out.
i tried (Ax+B)cos2x + (Cx+D)sin2x it all canceled out too
then...