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Newton's second law

 Definition/Summary Net force = rate of change of momentum (= mass times acceleration of the centre of mass, if the mass is constant) Net impulse = change of momentum These are vector equations, so they apply to each direction individually The rotational versions are: net torque = rate of change of angular momentum net impulsive torque = change of angular momentum

 Equations Newton's second law: $$\sum_{\text{all}}\mathbf{F}\,=\,\frac{d(m\mathbf{v}_{c.o.m.})}{dt}$$ If m is constant: $$\sum_{\text{all}}\mathbf{F}\,=\,m\frac{d(\mathbf{v}_{c.o.m.})}{dt}\,=\,m \mathbf{a}_{c.o.m.}$$ Torque version: $$\sum_{\text{all}}\mathbf{\tau}\,=\,\frac{d\mathbf{\mathcal{L}}}{dt}$$ Torque version for rigid body: $$\sum_{\text{all}}\mathbf{\tau}\,=\,I\mathbf{\alpha}$$

 Scientists Sir Isaac Newton (1643-1727)

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 Breakdown Physics > Classical Mechanics >> Newtonian Dynamics

 See Also elastic collisioninelastic collisionmomentsmomentum (non-relativiscentripetal acceleratio

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 Extended explanation Net force = mass times acceleration: This only applies when the mass is constant. For example, it does not apply to a rocket, whose mass is continually reduced by the burning of fuel. "Acceleration" means the acceleration of the centre of mass: this even applies when the body is rotating: the sum of the (linear) forces equals the mass times the (linear) acceleration of the c.o.m.: $$\sum\mathbf{F}\ =\ m\,\mathbf{a}_{c.o.m.}$$ Standard (non-impulsive) version: Newton's second law states that the total vector sum of the forces on a body is equal to the rate of change of its momentum. This formulation is valid when mass changes, and is even valid at relativistic speeds.$$\sum\mathbf{F}\ =\ \frac{d(m\mathbf{v})}{dt}$$Component version: Force and momentum are vectors, so Newton's second law is a vector equation. That means that it applies to the components in any direction, and so the law can also be written: In any direction, the total sum of the components of the forces on a body in that direction is equal to the rate of change of the component of its momentum in that direction.$$\sum\mathbf{F}_k\ =\ \frac{d(m\mathbf{v}_k)}{dt}$$Torque: The vector nature of the equation also means that its cross-product with any fixed vector gives another vector equation: Net torque on a point particle = rate of change of angular momentum:$$\mathbf{\tau}_{total}\equiv\mathbf{r} \times \sum\mathbf{F}=\frac{d}{dt}(\mathbf{r} \times \mathbf{p})$$ Combining this with the strong version of Newton's third law (action is equal and opposite to reaction, and in the same line) gives: Net torque on a rigid body = rate of change of angular momentum:$$\mathbf{\tau}_{total}\equiv\sum\mathbf{r} \times \mathbf{F}=\frac{d}{dt}\left(\int\mathbf{r} \times d\mathbf{p}\right)= \frac{d \mathbf{\mathcal{L}}}{dt}$$ This is also a vector equation, of course, and so we may take one component at a time, to give the scalar equation: Net torque about any axis = rate of change of angular momentum about that axis.Impulsive version: Impulse is the integral of force times time. By comparison, work done is the integral of force times distance. Sometimes (for example, when a bat hits a ball), the force changes quickly, and it is difficult to measure it, but it is easy to measure the overall effect of the force. The impulse is that overall effect. Newton's second law states that the total vector sum of the impulses on a body is equal to the change of its momentum.Collisions, and conservation of momentum: A collision or explosion is impulsive, and there are no external impulsive forces in a collision or explosion (in particular, the sum of the external forces is zero ), so the impulsive version of the law states: Total momentum immediately before = total momentum immediately after:$$\sum m_i\,u_i\,=\,\sum m_i\,v_i$$ In other words: conservation of momentum applies to all collisions or explosions. By comparison, conservation of energy applies only to elastic collisions. Most collisions are not elastic. Static problems: When nothing moves, the momentum is constant, and so Newton's second law states: The total sum of the forces on a body in equilibrium is zero. This applies separately to each body in a system, or to the external forces on any combination of bodies. When there are only three forces, a vector triangle may be used. Sliding problems (normal components): When one body slides against another along a common flat surface, the acceleration normal (perpendicular) to that surface is zero. If the surface is curved, the acceleration normal to the surface is not zero, but is centripetal towards the instantaneous centre of curvature of the surface (note: this is a matter of geometry, not physics ). Accordingly, Newton's second law for normal components states: The total sum of the components of the normal forces on a sliding body on a flat surface is zero, and on a curved surface equals the mass times the centripetal acceleration.String problems: When a number of bodies are connected by a string (an inextensible "massless" cable), in a straight line, all have the same (vector) acceleration, and so the tension in the string can be ignored (as an internal force), and the bodies can be treated together as a single body with the same total mass and acceleration and subject only to the external forces. When the string goes over a "massless" pulley, so that the string is in two parts in different directions, and the tensions either side of the pulley are the same, the bodies still all have the same scalar acceleration, and the bodies can be treated together as a single body with the same total mass and acceleration and subject only to the components of the external forces along the string. When the string goes over a massive pulley, so that the string is in two parts in different directions, and the tensions either side of the pulley are different, the previous paragraph applies except that the pulley must be treated as a body with the same acceleration and with an effective mass equal to the moment of inertia divided by the radius squared: $m_{eff}\ =\ I/r^2$ (for a uniform cylindrical pulley, that is half the actual mass: $m_{eff}\ =\ m/2$).

Commentary

 tiny-tim @ 05:29 PM Mar19-12 Added torque and impulsive torque to Definition.

 tiny-tim @ 06:56 PM Nov21-10 Adopted anmol singh's correction, inserting "centre of mass". Added "String problems" to ext expl. Added torque version to Equations.

 anmol singh @ 06:57 AM Aug7-10 Correct equation is F(net)=mass.accelaration of centre of mass

 Redbelly98 @ 09:25 AM Jan19-09 Newton's 2nd Law applies to living things as well. Have you never seen homework problems about people in elevators? Newton's laws can be used to find the usual quantities: net force on, or acceleration of, the person in the elevator.

 Robtai @ 02:45 AM Jan19-09 As far as I know, Newtons second law is only for non-living items

 plakhapate @ 11:17 PM Nov22-08 Newtons Second Law is applicable for non-living items only. Are there any laws for living animals? EDIT(by tiny-tim): Newton's second law applies to all creatures: see the many forum threads about penguins on sleds! (and please don't give out email addresses on PF ) EDIT (by Redbelly98) I've taken the liberty of highlighting tiny-tim's edit. It seems people are not noticing it.

 tiny-tim @ 01:44 PM Oct13-08 Fixed LaTeX, no change.

 tiny-tim @ 01:29 PM Oct4-08 Library entries seem to have changed in style, and to have become more detailed, since this was first written, so I've decided to expand on the original rather terse version.

 loong159 @ 03:54 PM Jun7-08 [Total momentum before collision equal to total momentum after collision in an elastic collision] m1(u1) + m2(u2) = m1(v1) + m2(v2) [inelastic collision] [Same velocity after collision] m1(u1) + m2(u2) = (m1+m2) x v [In an explosion] m1(-v1) + m2(v2) = 0

 @ 07:00 AM Jun2-08 Actually you all could write that Newton's Second Law states:"The rate of change of momentum is directly proportional to the force applied and the change in momentum is in the direction in which the force is applied. You have also missed that in a vertically travelling rocket the mass decreases

 tiny-tim @ 05:29 PM May13-08 Added reference to cross-product and angular momentum.

 Poseidon @ 02:09 PM May12-08 This is rather interesting in that,in my studies, I've been reading a book entitled "The Forensic Engineering Reconstruction of Accidents" and in chapter 4, entitled "Forensic Mechanics", that same eqution is mentioned.

 Hootenanny @ 07:29 AM May10-08 Changed "object or system of objects" to "body".

 Hootenanny @ 07:14 AM May10-08 My editions were to add bold face to the vector quantities in the equations and correct the definition and extended explanation: Originally: "Newton's second law states that the total of the forces on an object or system of objects is equal to the total change of their momentum." Changed to: "Newton's second law states that the total vector sum of the forces on an object or system of objects is equal to the rate of change of their momentum."