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algebraic field

Definition/Summary
A field is a commutative division ring.

That is, a commutative ring (a group under addition, and with multiplication, a multiplicative identity, and associative and distributive rules) in which division (the inverse of multiplication) is defined, except for division by zero.

So the non-zero elements of a field form a group under multiplication.

Note this is not the same notion as, say, an electromagnetic field in physics.

Equations
A ring is a set, closed under operations [itex]+[/itex] and [itex]\cdot[/itex], with identity elements 0 and 1 respectively, with inverses under [itex]+[/itex], and with the following rules:

Associative:
[tex]a\ +\ (b\ +\ c)\ =\ (a\ +\ b)\ +\ c[/tex]
[tex]a\ \cdot\ (b\ \cdot\ c)\ =\ (a\ \cdot\ b)\ \cdot\ c[/tex]

Distributive:
[tex]a\ \cdot\ (b\ +\ c)\ =\ (a\ \cdot\ b)\ +\ (a\cdot\ c)[/tex]
[tex](b\ +\ c)\ \cdot\ a\ =\ (b\ \cdot\ a)\ +\ (c\cdot\ a)[/tex]

A commutative ring also has the rules:

Commutative:
[tex]a\ +\ b\ =\ b\ +\ a[/tex]
[tex]a\ \cdot\ b\ =\ b\ \cdot\ a[/tex]

Scientists

Recent forum threads on algebraic field
 
Breakdown
Mathematics
> Algebra
>> Field Theory

See Also

Images

Extended explanation
Fields

Conventions and definitions

It is traditional to denote a generic field by [itex]\mathbb{F}[/itex], or [itex]k[/itex]. We shall use [itex]k[/itex] in this topic.

Definition
A field [itex]k[/itex] is a commutative ring where the non-zero elements form a group under multiplication. By convention fields must have at least two distinct elements: [itex]0[/itex] the additive identity; [itex]1[/itex] the multiplicative identity.


Examples

Examples abound since fields are some of the most important objects in mathematics.

1) The rational numbers [itex]\mathbb{Q}[/itex]

2) The real numbers [itex]\mathbb{R}[/itex]

3) The complex numbers [itex]\mathbb{C}[/itex]

4) For each prime [itex]p[/itex] in [itex]\mathbb{N}[/itex], the finite field [itex]\mathbb{F}_p[/itex], or [itex]GF(p)[/itex].

5) The algebraic numbers: the set of all roots of polynomial equations with rational coefficients.

Field Extensions

Given some field [itex]k[/itex], one frequently wishes to extend the field. An example of when might wish to do this is to allow more polynomials to have roots. For example, consider the field [itex]\mathbb{F}_p[/itex]. By Fermat's little theorem, the polynomial

[tex]f(x)=x^p-x+1[/tex]

has no roots in the field [itex]\mathbb{F}_p[/itex]. We may declare [itex]\alpha[/itex] to be a symbol that satisfies [itex]f[/itex], and form the field [itex]\mathbb{F}_p[\alpha][/itex]. Elements of this extension are formal linear combinations (i.e. with coefficients in [itex]\mathbb{F}_p[/itex]) of powers of [itex]\alpha[/itex], with the rule that [itex]f(\alpha)=0[/itex].

Equivalently, one could define this as the quotient of a polynomial ring:

[tex]\frac{\mathbb{F}_p[x]}{x^p-x+1}[/tex].

If [itex]x^p-x+1[/itex] is irreducible (e.g. if [itex]p=2[/itex] then this is a field wth [itex]p^p[/itex] elements. One can construct fields with [itex]p^r[/itex] elements for any [itex]r[/itex] by quotienting the polyonomial ring by any irreducible poly of degree [itex]r[/itex]. Of course the reader must take on trust here that there is an irreducible polynomial of each degree. The field with [itex]p^r[/itex] elements is a subfield of the field with [itex]p^s[/itex] elements if and only if [itex]r[/itex] divides [itex]s[/itex].

Number fields

One important and well understood class of field extensions are number fields. These merit a separate entry on their own.

Algebraic closures

Definition
A field [itex]k[/itex] is algebraically closed if any polyomial with coefficients in [itex]k[/itex] has a root in [itex]k[/itex].

Remark
Note, by the euclidean algorithm this implies that any polynomial has all its roots in [itex]k[/itex], and is the product (essentially uniquely) of linear factors with coefficients in [itex]k[/itex]. In particular, over an algebraically closed field a polynomial of degree [itex]r[/itex] has [itex]r[/itex] roots (with multiplicity). Contrast this to the ring [itex]\mathbb{Z}/8\mathbb{Z}[/itex] where the polynomial [itex]x^2-1[/itex] has more than 2 roots: 1,3,5 and 7 are all square roots of 1.

Examples

The complex numbers, and algebraic numbers are algebraically closed. No other field in our list of examples is algebraically closed.

Given an arbitrary field, [itex]k[/itex], we define its algebraic closure to be the smallest algebraically closed field containing [itex]k[/itex]. It is not clear a priori that one can always form the algebraic closure of [itex]k[/itex]. Indeed, one needs to appeal to the axiom of choice in general.

Note that there are no algebraically closed finite fields.

Characteristic of a field

The examples given above of [itex]\mathbb{F}_p[/itex] are so-called fields of positive characteristic.

Definition
Let [itex]k[/itex] be a field. Its characteristic is the minimal integer [itex]m[/itex] such that [itex]1[/itex] added to itself [itex]m[/itex] times is equal to [itex]0[/itex]. If no such [itex]m[/itex] exists, we say [itex]k[/itex] has characteristic zero.

It is usually an introductory exercise to show that [itex]m[/itex] is prime if it is non-zero.

Commentary

matt grime @ 04:07 PM Mar10-09
It is incorrect to call this topic 'algebraic field'. No one would use that term. Field (mathematics) would be infinitely preferable.

The assertion that a vector space is a module over a field belongs in the topic Vector Space - it is pointless here. There was also a reference to a (physical) field being defined over a vector space that seemed a little lax in its wording. Does one really mean 'over'? It was especially odd given the previous use of the same phrase to mean something else.

The latex appears to be knackered for me again. I remember this being an issue in the past.

tiny-tim @ 06:00 AM Jul24-08
Added associative distributive and commutative equations, and references to vector spaces.
Changed title to "algebraic field".

tiny-tim @ 06:46 PM Jul23-08
The title "fields" is positively misleading in an autolinked library.
The Recent forum threads on fields quotes five threads on electromagnetic or quantum field theory, which have nothing to do with algebraic fields.
If PF members are using the autolinking, they must be rather disappointed!
Perhaps the title should be "algebraic fields", to avoid false positives on autolinking?

Kurdt @ 07:13 PM Jun8-08
Autolinking only works on the forums matt, so you'll have to use good old url tags.

EDIT: Added link to Fermat's little theorem.

matt grime @ 05:37 PM Jun8-08
Hmm, how does this autolinking thing work again? I deliberately put in the reference to Fermat's little theorem with the aim of it autolinking to the article on that. (I tried using Fermats little theorem, as the article is incorrectly called, as well.)

Greg Bernhardt @ 01:20 PM Jun8-08
someone want to edit the breakdown, works in firefox